Решите уравнение: 6c^4-35=11c^2.

\[6c^{4} - 11c^{2} - 35 = 0\]

\[c^{2} = x \geq 0:\]

\[6x^{2} - 11x - 35 = 0\]

\[D = 121 + 840 = 961 = 31^{2}\]

\[x_{1} = \frac{11 - 31}{12} = - \frac{20}{12} < 0;\]

\[x_{2} = \frac{11 + 31}{12} = \frac{42}{12} = \frac{21}{6};\]

\[c^{2} = \frac{21}{6}\]

\[c = \pm \sqrt{\frac{21}{6}} = \pm \frac{\sqrt{126}}{6}.\]

\[Ответ:c = \pm \frac{\sqrt{126}}{6}.\]