Решите уравнение (8y-12)(2,1+0,3y)=0.

\[(8y - 12)(2,1 + 0,3y) = 0\]

\[8y - 12 = 0\ \ \ \ \ \ \ \ \ \ \ 2,1 + 0,3y = 0\]

\[8y = 12\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0,3y = - 2,1\]

\[y = \frac{12}{8}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ y = - \frac{21}{3}\]

\[y = 1,5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ y = - 7\]

\[Ответ:y = - 7;\ \ y = 1,5.\]