Решите уравнение: x^2+4x-10=0.

\[x² + 4x - 10 = 0\]

\[D = 4^{2} - 4 \cdot 1 \cdot ( - 10) =\]

\[= 16 + 40 = 56\]

\[x_{1} = \frac{- 4 + \sqrt{56}}{2 \cdot 1} = \frac{- 4 + 2\sqrt{14}}{2} =\]

\[= - 2 + \sqrt{14}\]

\[x_{2} = \frac{- 4 - \sqrt{56}}{2 \cdot 1} = \frac{- 4 - 2\sqrt{14}}{2} =\]

\[= - 2 - \sqrt{14}\]

\[Ответ:x = - 2 \pm \sqrt{14}\text{.\ }\]