Решите уравнение: (6-2x)^2=3x-9.

\[(6 - 2x)^{2} = 3x - 9\]

\[36 - 24x + 4x^{2} = 3x - 9\]

\[4x^{2} - 27x + 45 = 0\]

\[D = 729 - 720 = 9\]

\[x_{1} = \frac{27 + 3}{8} = \frac{30}{8} = 3\frac{3}{4} = 3,75;\]

\[x_{2} = \frac{27 - 3}{8} = \frac{24}{8} = 3.\]