Решите уравнение: 2x^3-8x^2+5x-20=0.

\[2x^{3} - 8x^{2} + 5x - 20 = 0\]

\[2x^{2}(x - 4) + 5(x - 4) = 0\]

\[(x - 4)\left( 2x^{2} + 5 \right) = 0\]

\[1)\ x - 4 = 0\]

\[x = 4.\]

\[2)\ 2x^{2} + 5 = 0\]

\[2x^{2} = - 5\]

\[нет\ корней.\]

\[Ответ:x = 4.\]