Решите уравнение: (5x-2)/(x-3)-(x-18)/(x-3)=0.

\[\frac{5x - 2}{x - 3} - \frac{x - 18}{x - 3} = 0\]

\[\frac{5x - 2 - x + 18}{x - 3} = 0\]

\[\frac{4x + 16}{x - 3} = 0;\ \ x
eq 3\]

\[4x + 16 = 0\]

\[4x = - 16\]

\[x = - 4.\]

\[Ответ:x = - 4.\]