Решите уравнение: 4x^4+12x^3-4x^2-12x=0.

\[4x^{4} + 12x^{3} - 4x^{2} - 12x = 0\]

\[4x^{3}(x + 3) - 4x(x + 3) = 0\]

\[(x + 3)\left( 4x^{3} - 4x \right) = 0\]

\[4x(x + 3)\left( x^{2} - 1 \right) = 0\]

\[4x(x + 3)(x - 1)(x + 1) = 0\]

\[x = 0;\ \ \ x = - 3;\ \ \ x = 1;\ x = - 1\]

\[Ответ:x = - 3;\ \ x = 0;\ \ x = \pm 1.\]