Решите уравнение: x^5-4x^4+4x^3-x^2+4x-4=0.

\[\left( x^{2} - 4x + 4 \right)\left( x^{3} - 1 \right) = 0\]

\[(x - 2)^{2}\left( x^{3} - 1 \right) = 0\]

\[x = 2\ \ \ \ \ \ \ \ \ \ \ x^{3} = 1\ \ \]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = 1\]

\[Ответ:x = 2;x = 1.\]