\[\frac{3}{x - 2} - \frac{13}{x^{2} + 2x + 4} = \frac{26 + 5x}{x^{3} - 8}\]
\[3x^{2} - 7x + 38 - 26 - 5x = 0\]
\[3x² - 12x + 12 = 0\ \ |\ :3\]
\[x^{2} - 4x + 4 = 0\]
\[(x - 2)^{2} = 0\]
\[x - 2 = 0\]
\[x = 2 \Longrightarrow не\ подходит.\]
\[Ответ:нет\ решения.\]