Решите уравнение: 36x^3-84x^2+49x=0.

\[36x^{3} - 84x^{2} + 49x = 0\]

\[x\left( 36x^{2} - 84x + 49 \right) = 0\]

\[x(6x - 7)^{2} = 0\]

\[x = 0;\ \]

\[6x - 7 = 0\]

\[6x = 7\]

\[x = \frac{7}{6} = 1\frac{1}{6}.\]

\[Ответ:x = 0;x = 1\frac{1}{6}.\]