Решите уравнение: (2x-3)^2-36=0.

\[(2x - 3)^{2} - 36 = 0\]

\[(2x - 3 - 6)(2x - 3 + 6) = 0\]

\[(2x - 9)(2x + 3) = 0\]

\[2x - 9 = 0\ \ \ \ \ \ \ \ \ 2x + 3 = 0\]

\[2x = 9\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2x = - 3\]

\[x = 4,5\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = - 1,5\]

\[Ответ:x = 4,5;x = - 1,5.\ \]