Решите уравнение: (2x^2-5x-7)(x-1)=0.

\[\left( 2x^{2} - 5x - 7 \right)(x - 1) = 0\]

\[x - 1 = 0;\ \ \ \ \ \ x = 1.\]

\[2x^{2} - 5x - 7 = 0\]

\[D = ( - 5)^{2} - 4 \cdot 2 \cdot ( - 7) =\]

\[= 25 + 56 = 81;\ \ \ \sqrt{D} = 9.\]

\[x_{1} = \frac{5 + 9}{2 \cdot 2} = \frac{14}{4} = \frac{7}{2} = 3,5;\ \ \ \ \ \]

\[x_{2} = \frac{5 - 9}{2 \cdot 2} = \frac{- 4}{4} = - 1\]

\[Ответ:1;3,5;\ - 1.\]