\[\frac{1^{\backslash x - 7}}{x - 5} - \frac{1^{\backslash x - 5}}{x - 7} = \frac{1^{\backslash x - 3}}{x - 1} - \frac{1^{\backslash x - 1}}{x - 3}\]
\[\frac{x - 7 - x + 5}{(x - 5)(x - 7)} = \frac{x - 3 - x + 1}{(x - 1)(x - 3)}\]
\[- 16x + 64 = 0\]
\[16x = 64\]
\[x = 4\]
\[Ответ:4.\]