Решите уравнение: -3x^2+10x-3=0.

Question

\[- 3x^{2} + 10x - 3 = 0\ \]

\[D = 100 - 36 = 64\]

\[x_{1,2} = \frac{- 10 \pm 8}{- 6}\]

\[x_{1} = \frac{- 2}{- 6} = \frac{1}{3};\ \ \ \ x_{2} = \frac{- 18}{- 6} = 3.\]

Accepted Answer

\[- 3x^{2} + 10x - 3 = 0\ \]

\[D = 100 - 36 = 64\]

\[x_{1,2} = \frac{- 10 \pm 8}{- 6}\]

\[x_{1} = \frac{- 2}{- 6} = \frac{1}{3};\ \ \ \ x_{2} = \frac{- 18}{- 6} = 3.\]

Ответ: