Решите уравнение: |3x-1|+x=2.

\[|3x - 1| + x = 2\]

\[\left\{ \begin{matrix} - 3x + 1 + x = 2 \\ 3x - 1 < 0\ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ }\]

\[\left\{ \begin{matrix} - 2x = 1 \\ x < \frac{1}{3}\text{\ \ \ \ \ \ } \\ \end{matrix} \right.\ \text{\ \ \ \ }\]

\[\left\{ \begin{matrix} x = - \frac{1}{2} \\ x < \frac{1}{3}\text{\ \ \ \ } \\ \end{matrix} \right.\ \]

\[Ответ:\frac{3}{4};\ - \frac{1}{2}.\]