Решите уравнение |1-3x|=37

\[\ |1 - 3x| = 37\]

\[1 - 3x = 37\]

\[- 3x = 36\]

\[x = - 12\]

\[1 - 3x = - 37\]

\[- 3x = - 38\]

\[x = \frac{38}{3} = 12\frac{2}{3}\]

\[Ответ:\ \ \ x = - 12\ \ \ \ \ и\ \ x = 12\frac{2}{3}.\]

\[\ |2x - 1| < 3\]

\[\left\{ \begin{matrix} 2x - 1 < 3\ \ \ \\ 2x - 1 > - 3 \\ \end{matrix}\text{\ \ \ \ \ \ \ \ \ \ \ \ } \right.\ \left\{ \begin{matrix} 2x < 4\ \ \ \\ 2x > - 2 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\left\{ \begin{matrix} x < 2\ \ \ \\ x > - 1 \\ \end{matrix} \right.\ \]

\[Ответ:\ \ \ x \in ( - 1;\ \ 2).\]