Решите неравенство |6x+2|>=5

\[\ |6x + 2| \geq 5\]

\[\left\lbrack \begin{matrix} 6x + 2 \geq 5\ \ \ \\ 6x + 2 \leq - 5 \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\left\lbrack \begin{matrix} 6x \geq 3\ \ \ \\ 6x \leq - 7 \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\left\lbrack \begin{matrix} x \geq \frac{1}{2}\text{\ \ \ \ } \\ x \leq - \frac{7}{6} \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\]

\[\ \left\lbrack \begin{matrix} x \geq \frac{1}{2}\text{\ \ \ \ \ \ \ } \\ x \leq - 1\frac{1}{6} \\ \end{matrix} \right.\ \]

\[Ответ:\ \ \ \ x \in \left( - \infty;\ - 1\frac{1}{6} \right\rbrack\ \ \cup \lbrack 0,5;\ \ \ + \infty).\]

\[\frac{1}{7}x < 1\]

\[x < 7.\]