Решите систему уравнений: 9x^2-6xy+y^2=16; 3x^2-xy=8.

\[3x^{2} - x(3x - 4) = 8\]

\[3x^{2} - 3x^{2} + 4x = 8\]

\[4x = 8\]

\[x = 2\]

\[3x^{2} - x(3x + 4) = 8\]

\[3x^{2} - 3x^{2} - 4x = 8\]

\[- 4x = 8\]

\[x = - 2.\]

\[x_{2} = - 2 \Longrightarrow \text{\ \ \ \ }\]

\[\Longrightarrow \ y_{2} = 3 \bullet ( - 2) + 4 =\]

\[= - 6 + 4 = - 2.\]

\[Ответ:(2;2),\ ( - 2;\ - 2).\]