Решите систему уравнений: 6(x-3)=7y-1; 2(y+6)=3x+2.

\[\left\{ \begin{matrix} 6(x - 3) = 7y - 1 \\ 2(y + 6) = 3x + 2 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 6x - 18 = 7y - 1 \\ 2y + 12 = 3x + 2 \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\]

\[\left\{ \begin{matrix} 6x - 7y = 17\ \ \ \ \ \ \ \ \ \ \ \\ 3x - 2y = 10\ | \cdot 2\ \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 6x - 7y = 17 \\ 6x - 4y = 20 \\ \end{matrix} \right.\ - \ \ \ \ \ \]

\[\left\{ \begin{matrix} - 3y = - 3\ \ \ \ \\ x = \frac{20 + 4y}{6} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 1 \\ x = 4 \\ \end{matrix} \right.\ \]

\[Ответ:(4;1).\]