Вопрос:

Решите систему уравнений: x/3-y/2=8; 3x/8+y/4=22.

Ответ:

\[\left\{ \begin{matrix} \frac{x}{3} - \frac{y}{2} = 8\ \ \ \ \ \ \ \ \ \ | \cdot 6 \\ \frac{3x}{8} + \frac{y}{4} = 22\ \ \ \ | \cdot 8\ \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\]

\[\left\{ \begin{matrix} 2x - 3y = 48\ \ \ \ \ | \cdot 2 \\ 3x + 2y = 176\ \ \ | \cdot 3 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 4x - 6y = 96\ \ \ \\ 9x + 6y = 528 \\ \end{matrix} \right.\ +\]

\[13x = 624\]

\[x = 48.\]

\[3y = 2x - 48\]

\[3y = 2 \cdot 48 - 48\]

\[3y = 48\]

\[y = 16.\]

\[\left\{ \begin{matrix} x = 48 \\ y = 16 \\ \end{matrix} \right.\ \]

\[Ответ:(48;16).\]


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