Вопрос:

Решите систему уравнений: 4(m+2)=1-5n; 3(n+2)=5-2m.

Ответ:

\[\left\{ \begin{matrix} 4(m + 2) = 1 - 5n \\ 3(n + 2) = 5 - 2m \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 4m + 8 = 1 - 5n \\ 3n + 6 = 5 - 2m \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 4m + 5n = - 7\ \ \ \ \ \ \ \ \ \ \ \\ 2m + 3n = - 1\ \ \ \ | \cdot 2 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 4m + 5n = - 7 \\ 4m + 6n = - 2 \\ \end{matrix} - \right.\ \text{\ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - n = - 5\ \ \ \ \ \ \ \ \\ m = \frac{- 1 - 3n}{2} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} n = 5\ \ \ \ \ \\ m = - 8 \\ \end{matrix} \right.\ \]

\[Ответ:( - 8;5).\]


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