Решите систему уравнений: x/2-y/3=1; x/4+2y/3=8.

\[\left\{ \begin{matrix} \frac{x}{2} - \frac{y}{3} = 1\ \ \ \ \ \ \ \ | \cdot 6 \\ \frac{x}{4} + \frac{2y}{3} = 8\ \ \ | \cdot 12 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 3x - 2y = 6\ \ \ \\ 3x + 8y = 96 \\ \end{matrix} - \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} - 10y = - 90 \\ x = \frac{96 - 8y}{3} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 9 \\ x = 8 \\ \end{matrix} \right.\ \]

\[Ответ:(8;9).\]