Решите систему уравнений: (2x)^2+y^2=18; -x^2+3y=-9.

\[y^{2} + 6y = 0\]

\[y(y + 6) = 0\]

\[y_{1} = 0;\ \ \ y_{2} = - 6.\]

\[- x_{1}^{2} + 3 \cdot 0 = - 9\]

\[x_{1}^{2} = 9\]

\[x_{1} = \pm 3.\]

\[- x_{2}^{2} + 3 \cdot ( - 6) = - 9\]

\[- x_{2}^{2} = - 9 + 18 \Longrightarrow \varnothing\]

\[Ответ:( - 3;0);(3;0).\]