Решите систему способом подстановки: 1+2(x-y)=3x-4y; 10-4(x+y)=3y-3x.

\[\left\{ \begin{matrix} 1 + 2(x - y) = 3x - 4y \\ 10 - 4(x + y) = 3y - 3x \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 1 + 2x - 2y = 3x - 4y\ \ \ \\ 10 - 4y - 4x = 3y - 3x \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} x - 2y = 1\ \ \ \\ x + 7y = 10 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} x = 1 + 2y\text{\ \ \ \ \ \ \ \ \ \ \ \ \ } \\ 1 + 2y + 7y = 10 \\ \end{matrix} \right.\ \]

\[9y = 9\]

\[y = 1.\]

\[x = 1 + 2y = 1 + 2 = 3.\]

\[Ответ:(3;1).\]