Решите систему неравенств: x^2-3x-10<=0; x>1.

Ответ:

\[\left\{ \begin{matrix} x² - 3x - 10 \leq 0\ \ (1) \\ x > 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[(1)\ x_{1} + x_{2} = 3,\ \ \ \ x_{1} \cdot x_{2} = - 10\]

\[x_{1} = 5,\ \ x_{2} = - 2\]

\[Ответ:(1;5\rbrack.\]