Решите систему неравенств: (3x^2-64)/(9x^2-1)>(x-64)/(9x^2-1); (x+1005)/(6x-5)<(x-1002)/(6x-5).

\[\left\{ \begin{matrix} \frac{3x^{2} - 64}{9x^{2} - 1} > \frac{x - 64}{9x^{2} - 1}\text{\ \ \ } \\ \frac{x + 1005}{6x - 5} < \frac{x - 1002}{6x - 5} \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} \frac{3x^{2} - x}{9x^{2} - 1} > 0 \\ \frac{2007}{6x - 5} < 0\ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} \frac{x(3x - 1)}{(3x - 1)(3x + 1)} > 0 \\ 6x - 5 < 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} \frac{3x\left( x - \frac{1}{3} \right)}{9 \cdot \left( x - \frac{1}{3} \right)\left( x + \frac{1}{3} \right)} > 0 \\ x < \frac{5}{6}\text{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ } \\ \end{matrix} \right.\ \]