Решите неравенство: x-(x-3)/4+(x+1)/8>2.

\[x - \frac{x - 3}{4} + \frac{x + 1}{8} > 2\ \ \ \ | \cdot 8\]

\[8x - 2 \cdot (x - 3) + x + 1 > 16\]

\[8x - 2x + 6 + x + 1 > 16\]

\[7x > 9\]

\[x > \frac{9}{7}\]

\[x > 1\frac{2}{7}\]

\[Ответ:x > 1\frac{2}{7}.\]