Решите неравенство: 2x/3-(x-1)/6+(x+2)/2>=0.

\[\frac{2x}{3} - \frac{x - 1}{6} + \frac{x + 2}{2} \geq 0\ \ \ \ | \cdot 6\]

\[2 \cdot 2x - (x - 1) + 3 \cdot (x + 2) \geq 0\]

\[4x - x + 1 + 3x + 6 \geq 0\]

\[3x + 3x + 7 \geq 0\]

\[6x \geq - 7\]

\[x \geq - \frac{7}{6}\]

\[x \geq - 1\frac{1}{6}\]

\[Ответ:x \geq - 1\frac{1}{6}.\]