Решите неравенство: (x^2-9)(x^2-5x+6)<=0.

\[\left( x^{2} - 9 \right)\left( x^{2} - 5x + 6 \right) \leq 0\]

\[x^{2} - 5x + 6 =\]

\[= x^{2} - 3x - 2x + 6 =\]

\[= x(x - 3) - 2(x - 3) =\]

\[= (x - 3)(x - 2)\]

\[(x - 3)^{2}(x + 3)(x - 2) \leq 0\ \]

\[Ответ:\lbrack - 3;2\rbrack \cup \left\{ 3 \right\}.\]