Решите неравенство: (x^3-3x^2-25x+75)/(3-x)>=0.

\[\frac{x^{3} - 3x^{2} - 25x + 75}{3 - x} \geq 0\]

\[\frac{x^{2}(x - 3) - 25 \cdot (x - 3)}{- (x - 3)} \geq 0\]

\[\frac{(x - 3)(x^{2} - 25)}{- (x - 3)} \geq 0\]

\[\frac{(x - 3)(x - 5)(x + 5)}{x - 3} \leq 0\]

\[Ответ:\lbrack - 5;3) \cup (3;5\rbrack.\]