Решите неравенство: x^2-5x+6>=0.

\[x^{2} - 5x + 6 \geq 0\]

\[x_{1} + x_{2} = 5;\ \ x_{1} \cdot x_{2} = 6\]

\[x_{1} = 2;\ \ x_{2} = 3;\]

\[(x - 2)(x - 3) \geq 0\]

\[x \leq 2;\ \ x \geq 3.\]

\[Ответ:x \leq 2;\ \ x \geq 3.\]