Решите неравенство: (x^2-2x)(6x+3)<=0.

\[\left( x^{2} - 2x \right)(6x + 3) \leq 0\]

\[6x(x - 2)\left( x + \frac{1}{2} \right) \leq 0\]

\[Ответ:( - \infty;\ - 0,5\rbrack \cup \lbrack 0;2\rbrack.\]