Решите неравенство: (3x-1)/(x+2)>1.

\[\frac{3x - 1}{x + 2} > 1\]

\[\frac{3x - 1}{x + 2} - 1^{\backslash x + 2} > 0\]

\[\frac{3x - 1 - x - 2}{x + 2} > 0\]

\[\frac{2x - 3}{x + 2} > 0\]

\[\frac{2 \cdot (x - 1,5)}{x + 2} > 0\]

\[Ответ:( - \infty; - 2) \cup (1,5; + \infty).\]