Решите неравенство: (x^2-2x-7)^2<(x^2-6x-3)^2.

\[\left( x^{2} - 2x - 7 \right)^{2} < \left( x^{2} - 6x - 3 \right)^{2}\]

\[(4x - 4)\left( 2x^{2} - 8x - 10 \right) < 0\]

\[8 \cdot (x - 1)\left( x^{2} - 4x - 5 \right) < 0\]

\[8 \cdot (x - 1)(x - 5)(x + 1) < 0\]

\[Ответ:( - \infty;\ - 1) \cup (1;5).\]