Решите неравенство: x^2+7x-30<=0.

\[x^{2} + 7x - 30 \leq 0\]

\[x_{1} + x_{2} = - 7;\ \ x_{1} \cdot x_{2} = - 30\]

\[x_{1} = - 10;\ \ x_{2} = 3.\]

\[(x + 10)(x - 3) \leq 0\]

\[- 10 \leq x \leq 3.\]

\[Ответ:\ - 10 \leq x \leq 3.\]