Решите неравенство: 16x^2-25>0.

\[16x^{2} - 25 > 0\]

\[16\left( x^{2} - \frac{25}{16} \right) > 0\]

\[16\left( x + \frac{5}{4} \right)\left( x - \frac{5}{4} \right) > 0\]

\[x < - 1,25;\ \ x > 1,25.\]

\[Ответ:x < - 1,25;x > 1,25.\]