Решите неравенство: (x^2+3x-10)^2<(x^2+x-6)^2.

\[\left( x^{2} + 3x - 10 \right)^{2} < \left( x^{2} + x - 6 \right)^{2}\]

\[(2x - 4)\left( 2x^{2} + 4x - 16 \right) < 0\]

\[4 \cdot (x - 2)\left( x^{2} + 2x - 8 \right) < 0\]

\[4 \cdot (x - 2)(x - 2)(x + 4) < 0\]

\[4 \cdot (x - 2)^{2}(x + 4) < 0\]

\[Ответ:( - \infty; - 4).\]