Решите неравенство: (x+4)(x-2)(3-x)<0.

\[(x + 4)(x - 2)(3 - x) < 0\]

\[(x + 4)(x - 2)(x - 3) > 0\]

\[x + 4 = 0\]

\[x = - 4\]

\[x - 2 = 0\]

\[x = 2\]

\[x - 3 = 0\]

\[x = 3\]

\[Ответ:( - 4;2) \cup (3; + \infty).\]