Решите неравенство: (x+2)(x-1)(3x-7)<=0.

\[(x + 2)(x - 1)(3x - 7) \leq 0\]

\[x + 2 = 0\]

\[x = - 2\]

\[x - 1 = 0\]

\[x = 1\]

\[3x - 7 = 0\]

\[x = 2\frac{1}{3}\]

\[Ответ:( - \infty; - 2\rbrack\left\lbrack 1;2\frac{1}{3} \right\rbrack.\]