Решите неравенство: (3x-4)(2x+5)/(x+1)>=0.

\[\frac{(3x - 4)(2x + 5)}{x + 1} \geq 0\]

\[\frac{6 \cdot \left( x - 1\frac{1}{3} \right)(x + 2,5)}{x + 1} \geq 0\]

\[Ответ:\lbrack - 2,5; - 1) \cup \left\lbrack 1\frac{1}{3}; + \infty \right).\]