Решите систему неравенств: (x+5)(2x-5)>0; (x+6)(3x-10)<=0.

\[\left\{ \begin{matrix} (x + 5)(2x - 5) > 0\ \ \ \\ (x + 6)(3x - 10) \leq 0 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} 2 \cdot (x + 5)(x - 2,5) > 0\ \\ 3 \cdot (x + 6)\left( x - 3\frac{1}{3} \right) \leq 0 \\ \end{matrix} \right.\ \]

\[Ответ:\ \ \lbrack - 6; - 5) \cup \left( 2,5;3\frac{1}{3} \right\rbrack.\]