Решите методом подстановки систему уравнений: 4x-y=1, 5x+3y=14.

\[\left\{ \begin{matrix} 4x - y = 1\ \ \ \ \\ 5x + 3y = 14 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 4x - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ 5x + 3 \cdot (4x - 1) = 14 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = 4x - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ 5x + 12x - 3 = 14 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} y = 4x - 1 \\ 17x = 17\ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} x = 1 \\ y = 3 \\ \end{matrix} \right.\ \]

\[Ответ:(1;3).\]