Решите квадратное уравнение: x^2+4x-5=0.

\[x^{2} + 4x - 5 = 0\]

\[D = 4^{2} - 4 \cdot 1 \cdot ( - 5) =\]

\[= 16 + 20 = 36\]

\[x_{1} = \frac{- 4 + \sqrt{36}}{2} = \frac{- 4 + 6}{2} = \frac{2}{2} =\]

\[= 1\]

\[x_{2} = \frac{- 4 - \sqrt{36}}{2} = \frac{- 4 - 6}{2} =\]

\[= \frac{- 10}{2} = - 5\]

\[Ответ:1;\ - 5.\]