Решите квадратное уравнение: 3x^2-5x-8=0.

\[3x^{2} - 5x - 8 = 0\]

\[D = ( - 5)^{2} - 4 \cdot 3 \cdot ( - 8) =\]

\[= 25 + 96 = 121\]

\[x_{1} = \frac{5 + \sqrt{121}}{2 \cdot 3} = \frac{5 + 11}{6} = \frac{16}{6} =\]

\[= \frac{8}{3} = 2\frac{2}{3}\]

\[x_{2} = \frac{5 - \sqrt{121}}{2 \cdot 3} = \frac{5 - 11}{6} =\]

\[= \frac{- 6}{6} = - 1\]

\[Ответ:2\frac{2}{3};\ - 1.\]