Решите квадратное уравнение: 2x^2-7x-9=0.

\[2x^{2} - 7x - 9 = 0\]

\[D = ( - 7)^{2} - 4 \cdot 2 \cdot ( - 9) =\]

\[= 49 + 72 = 121\]

\[x_{1} = \frac{7 + \sqrt{121}}{2 \cdot 2} = \frac{7 + 11}{4} = \frac{18}{4} =\]

\[= \frac{9}{2} = 4,5\]

\[x_{2} = \frac{7 - \sqrt{121}}{2 \cdot 2} = \frac{7 - 11}{4} = \frac{- 4}{4} =\]

\[= - 1\]

\[Ответ:4,5;\ - 1.\]