Решите графически систему уравнений y=2x-x^2; 2x+y=3.

Question

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Ответ:

Accepted Answer

\[\left\{ \begin{matrix} y = 2x - x^{2} \\ 2x + y = 3\ \ \\ \end{matrix} \right.\ \]

\[y = 2x - x^{2}\]

\[x_{0} = \frac{2}{2} = 1;\ y_{0} = 1\]

\[x\]	\[0\]	\[2\]	\[- 1\]
\[y\]	\[0\]	\[0\]	\[- 3\]

\[(1;1).\]

\[y = 3 - 2x\]

\[x\]	\[0\]	\[1\]
\[y\]	\[3\]	\[1\]

\[Ответ:(3;\ - 3);\ \ (1;1).\]