Решить уравнение: (8y-5)/y=9y/(y+2).

\[\frac{8y - 5}{y} = \frac{9y}{y + 2}\]

\[y \neq 0;\ \ \ y \neq - 2;\]

\[(8y - 5) \cdot (y + 2) = 9y \cdot y\]

\[8y^{2} - 5y + 16y - 10 = 9y^{2}\]

\[y^{2} - 11y + 10 = 0\]

\[y_{1} + y_{2} = 11;\ \ y_{1} \cdot y_{2} = 10\]

\[y_{1} = 1;\ \ y_{2} = 10.\]

\[Ответ:y = 1;y = 10.\]