Решить неравенство: 3x^2-5x-2>=0.

\[3x^{2} - 5x - 2 \geq 0\]

\[D = 25 + 24 = 49\]

\[x_{1} = \frac{5 + 7}{6} = 2;\]

\[x_{2} = \frac{5 - 7}{6} = - \frac{2}{6} = - \frac{1}{3};\]

\[3\left( x + \frac{1}{3} \right)(x - 2) \geq 0\]

\[x \leq - \frac{1}{3};\ \ x \geq 2.\]

\[Ответ:x \leq - \frac{1}{3};\ \ x \geq 2.\]