Разложите на множители квадратный трехчлен: 60y^2-20y-5.

\[60y² - 20y - 5 = 0\ \ \ |\ :5\]

\[12y^{2} - 4y - 1 = 0\]

\[D_{1} = 4 + 12 = 16\]

\[y_{1} = \frac{2 + 4}{12} = \frac{6}{12} = \frac{1}{2};\ \ \ \]

\[y_{2} = \frac{2 - 4}{12} = - \frac{2}{12} = - \frac{1}{6}.\]

\[60y^{2} - 20y - 5 =\]

\[= 60 \cdot \left( y - \frac{1}{2} \right)\left( y + \frac{1}{6} \right) =\]

\[= 5 \cdot (2y - 1)(6y + 1).\]