Приведите дробь 8/(b-3) к знаменателю: b^2-9.

Question

\[\frac{8}{b - 3} \cdot \frac{b + 3}{b + 3} = \frac{8 \cdot (b + 3)}{b^{2} - 9} =\]

\[= \frac{8b + 24}{b^{2} - 9}\]

Accepted Answer

\[\frac{8}{b - 3} \cdot \frac{b + 3}{b + 3} = \frac{8 \cdot (b + 3)}{b^{2} - 9} =\]

\[= \frac{8b + 24}{b^{2} - 9}\]

Ответ: